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156317693941 is a prime number
BaseRepresentation
bin1001000110010101000…
…0101011011111110101
3112221111001022121201001
42101211100223133311
510030114312201231
6155451130403301
714202461322013
oct2214520533765
9487431277631
10156317693941
1160326299112
1226366590531
13119823cc8b6
1477cc85b8b3
1540ed56db61
hex246542b7f5

156317693941 has 2 divisors, whose sum is σ = 156317693942. Its totient is φ = 156317693940.

The previous prime is 156317693933. The next prime is 156317693947. The reversal of 156317693941 is 149396713651.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132238413316 + 24079280625 = 363646^2 + 155175^2 .

It is a cyclic number.

It is not a de Polignac number, because 156317693941 - 23 = 156317693933 is a prime.

It is a super-2 number, since 2×1563176939412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (156317693947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78158846970 + 78158846971.

It is an arithmetic number, because the mean of its divisors is an integer number (78158846971).

Almost surely, 2156317693941 is an apocalyptic number.

It is an amenable number.

156317693941 is a deficient number, since it is larger than the sum of its proper divisors (1).

156317693941 is an equidigital number, since it uses as much as digits as its factorization.

156317693941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3674160, while the sum is 55.

The spelling of 156317693941 in words is "one hundred fifty-six billion, three hundred seventeen million, six hundred ninety-three thousand, nine hundred forty-one".