Base | Representation |
---|---|
bin | 1001000110101000111… |
… | …0100000110110001111 |
3 | 112221200212002121202012 |
4 | 2101222032200312033 |
5 | 10030302124341421 |
6 | 155503304251435 |
7 | 14204522445101 |
oct | 2215216406617 |
9 | 487625077665 |
10 | 156401012111 |
11 | 60369326303 |
12 | 2638a470b7b |
13 | 119967523a6 |
14 | 77d9949571 |
15 | 4105a2a95b |
hex | 246a3a0d8f |
156401012111 has 2 divisors, whose sum is σ = 156401012112. Its totient is φ = 156401012110.
The previous prime is 156401012039. The next prime is 156401012137. The reversal of 156401012111 is 111210104651.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 156401012111 - 214 = 156400995727 is a prime.
It is a super-2 number, since 2×1564010121112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (156401012011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78200506055 + 78200506056.
It is an arithmetic number, because the mean of its divisors is an integer number (78200506056).
Almost surely, 2156401012111 is an apocalyptic number.
156401012111 is a deficient number, since it is larger than the sum of its proper divisors (1).
156401012111 is an equidigital number, since it uses as much as digits as its factorization.
156401012111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 156401012111 its reverse (111210104651), we get a palindrome (267611116762).
The spelling of 156401012111 in words is "one hundred fifty-six billion, four hundred one million, twelve thousand, one hundred eleven".
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