Search a number
-
+
156505383137 is a prime number
BaseRepresentation
bin1001000111000001110…
…0101010000011100001
3112221222010111012212202
42101300130222003201
510031010334230022
6155521513302545
714210230543565
oct2216034520341
9487863435782
10156505383137
1160412232854
12263b9404a55
13119b22665ac
1478097576a5
15410ec95592
hex247072a0e1

156505383137 has 2 divisors, whose sum is σ = 156505383138. Its totient is φ = 156505383136.

The previous prime is 156505383031. The next prime is 156505383163. The reversal of 156505383137 is 731383505651.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112713961441 + 43791421696 = 335729^2 + 209264^2 .

It is a cyclic number.

It is not a de Polignac number, because 156505383137 - 220 = 156504334561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 156505383091 and 156505383100.

It is not a weakly prime, because it can be changed into another prime (156505383197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78252691568 + 78252691569.

It is an arithmetic number, because the mean of its divisors is an integer number (78252691569).

Almost surely, 2156505383137 is an apocalyptic number.

It is an amenable number.

156505383137 is a deficient number, since it is larger than the sum of its proper divisors (1).

156505383137 is an equidigital number, since it uses as much as digits as its factorization.

156505383137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134000, while the sum is 47.

Adding to 156505383137 its reverse (731383505651), we get a palindrome (887888888788).

The spelling of 156505383137 in words is "one hundred fifty-six billion, five hundred five million, three hundred eighty-three thousand, one hundred thirty-seven".