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15676314080653 is a prime number
BaseRepresentation
bin1110010000011110110100…
…1000011101010110001101
32001111122022021121101221101
43210013231020131112031
54023320042401040103
653201333235303101
73205401451055512
oct344075510352615
961448267541841
1015676314080653
114aa4318688416
121912211a4aa91
1389936847b215
143c2a4817b309
151c2b9c0bba1d
hexe41ed21d58d

15676314080653 has 2 divisors, whose sum is σ = 15676314080654. Its totient is φ = 15676314080652.

The previous prime is 15676314080591. The next prime is 15676314080671. The reversal of 15676314080653 is 35608041367651.

15676314080653 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14670148606569 + 1006165474084 = 3830163^2 + 1003078^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15676314080653 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15676314080594 and 15676314080603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15676314080683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7838157040326 + 7838157040327.

It is an arithmetic number, because the mean of its divisors is an integer number (7838157040327).

Almost surely, 215676314080653 is an apocalyptic number.

It is an amenable number.

15676314080653 is a deficient number, since it is larger than the sum of its proper divisors (1).

15676314080653 is an equidigital number, since it uses as much as digits as its factorization.

15676314080653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10886400, while the sum is 55.

The spelling of 15676314080653 in words is "fifteen trillion, six hundred seventy-six billion, three hundred fourteen million, eighty thousand, six hundred fifty-three".