Base | Representation |
---|---|
bin | 1110010000101101000101… |
… | …0101101100000001101101 |
3 | 2001112000012002221011021021 |
4 | 3210023101111230001231 |
5 | 4023400413021111101 |
6 | 53203205205134141 |
7 | 3205565361206263 |
oct | 344132125540155 |
9 | 61460162834237 |
10 | 15680142753901 |
11 | 4aa5a0289328a |
12 | 1912b000ba351 |
13 | 899828744752 |
14 | 3c2ccc854433 |
15 | 1c2d2329d5a1 |
hex | e42d156c06d |
15680142753901 has 2 divisors, whose sum is σ = 15680142753902. Its totient is φ = 15680142753900.
The previous prime is 15680142753853. The next prime is 15680142753923. The reversal of 15680142753901 is 10935724108651.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15606655676676 + 73487077225 = 3950526^2 + 271085^2 .
It is a cyclic number.
It is not a de Polignac number, because 15680142753901 - 223 = 15680134365293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15680142753931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7840071376950 + 7840071376951.
It is an arithmetic number, because the mean of its divisors is an integer number (7840071376951).
It is a 1-persistent number, because it is pandigital, but 2⋅15680142753901 = 31360285507802 is not.
Almost surely, 215680142753901 is an apocalyptic number.
It is an amenable number.
15680142753901 is a deficient number, since it is larger than the sum of its proper divisors (1).
15680142753901 is an equidigital number, since it uses as much as digits as its factorization.
15680142753901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 52.
The spelling of 15680142753901 in words is "fifteen trillion, six hundred eighty billion, one hundred forty-two million, seven hundred fifty-three thousand, nine hundred one".
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