Base | Representation |
---|---|
bin | 1001001001010111000… |
… | …0001011000011000001 |
3 | 120000120202011212001012 |
4 | 2102111300023003001 |
5 | 10033301100143001 |
6 | 200103552050305 |
7 | 14231600432036 |
oct | 2222560130301 |
9 | 500522155035 |
10 | 157131256001 |
11 | 60703552355 |
12 | 26552b33995 |
13 | 11a81b20775 |
14 | 786891738d |
15 | 4149bc42bb |
hex | 2495c0b0c1 |
157131256001 has 2 divisors, whose sum is σ = 157131256002. Its totient is φ = 157131256000.
The previous prime is 157131255991. The next prime is 157131256013. The reversal of 157131256001 is 100652131751.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152517586225 + 4613669776 = 390535^2 + 67924^2 .
It is an emirp because it is prime and its reverse (100652131751) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-157131256001 is a prime.
It is a super-2 number, since 2×1571312560012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (157131256901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78565628000 + 78565628001.
It is an arithmetic number, because the mean of its divisors is an integer number (78565628001).
Almost surely, 2157131256001 is an apocalyptic number.
It is an amenable number.
157131256001 is a deficient number, since it is larger than the sum of its proper divisors (1).
157131256001 is an equidigital number, since it uses as much as digits as its factorization.
157131256001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 32.
Adding to 157131256001 its reverse (100652131751), we get a palindrome (257783387752).
The spelling of 157131256001 in words is "one hundred fifty-seven billion, one hundred thirty-one million, two hundred fifty-six thousand, one".
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