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1572105414133 is a prime number
BaseRepresentation
bin10110111000001000110…
…010001110010111110101
312120021212201200200211101
4112320020302032113311
5201224132441223013
63202114255010101
7221403144351562
oct26701062162765
95507781620741
101572105414133
115567a9581241
12214826b09931
13b5330ac6227
1456139b3b869
152ad627418dd
hex16e08c8e5f5

1572105414133 has 2 divisors, whose sum is σ = 1572105414134. Its totient is φ = 1572105414132.

The previous prime is 1572105414097. The next prime is 1572105414233. The reversal of 1572105414133 is 3314145012751.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 996816537649 + 575288876484 = 998407^2 + 758478^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1572105414133 is a prime.

It is a super-2 number, since 2×15721054141332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1572105414092 and 1572105414101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1572105414233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 786052707066 + 786052707067.

It is an arithmetic number, because the mean of its divisors is an integer number (786052707067).

Almost surely, 21572105414133 is an apocalyptic number.

It is an amenable number.

1572105414133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1572105414133 is an equidigital number, since it uses as much as digits as its factorization.

1572105414133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 37.

The spelling of 1572105414133 in words is "one trillion, five hundred seventy-two billion, one hundred five million, four hundred fourteen thousand, one hundred thirty-three".