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157715492713 is a prime number
BaseRepresentation
bin1001001011100010010…
…0110110111101101001
3120002002110112011010221
42102320210312331221
510041000131231323
6200241542210041
714252223366052
oct2227044667551
9502073464127
10157715492713
1160983314009
1226696723921
1311b45b8a46c
1478c2359729
15418112b55d
hex24b8936f69

157715492713 has 2 divisors, whose sum is σ = 157715492714. Its totient is φ = 157715492712.

The previous prime is 157715492687. The next prime is 157715492717. The reversal of 157715492713 is 317294517751.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127329076224 + 30386416489 = 356832^2 + 174317^2 .

It is an emirp because it is prime and its reverse (317294517751) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 157715492713 - 233 = 149125558121 is a prime.

It is a super-3 number, since 3×1577154927133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (157715492717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78857746356 + 78857746357.

It is an arithmetic number, because the mean of its divisors is an integer number (78857746357).

Almost surely, 2157715492713 is an apocalyptic number.

It is an amenable number.

157715492713 is a deficient number, since it is larger than the sum of its proper divisors (1).

157715492713 is an equidigital number, since it uses as much as digits as its factorization.

157715492713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1852200, while the sum is 52.

The spelling of 157715492713 in words is "one hundred fifty-seven billion, seven hundred fifteen million, four hundred ninety-two thousand, seven hundred thirteen".