Base | Representation |
---|---|
bin | 1001001101111010111… |
… | …1000110101100100111 |
3 | 120010202002012201000021 |
4 | 2103132233012230213 |
5 | 10043303030302212 |
6 | 200425252300011 |
7 | 14304126230665 |
oct | 2233657065447 |
9 | 503662181007 |
10 | 158355712807 |
11 | 61181742926 |
12 | 26835011607 |
13 | 11c186c8b16 |
14 | 79433b1c35 |
15 | 41bc441307 |
hex | 24debc6b27 |
158355712807 has 2 divisors, whose sum is σ = 158355712808. Its totient is φ = 158355712806.
The previous prime is 158355712733. The next prime is 158355712817. The reversal of 158355712807 is 708217553851.
It is a strong prime.
It is an emirp because it is prime and its reverse (708217553851) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-158355712807 is a prime.
It is a super-2 number, since 2×1583557128072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (158355712817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 79177856403 + 79177856404.
It is an arithmetic number, because the mean of its divisors is an integer number (79177856404).
Almost surely, 2158355712807 is an apocalyptic number.
158355712807 is a deficient number, since it is larger than the sum of its proper divisors (1).
158355712807 is an equidigital number, since it uses as much as digits as its factorization.
158355712807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352000, while the sum is 52.
The spelling of 158355712807 in words is "one hundred fifty-eight billion, three hundred fifty-five million, seven hundred twelve thousand, eight hundred seven".
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