Base | Representation |
---|---|
bin | 10011000001001… |
… | …00100000111001 |
3 | 102010012010021211 |
4 | 21200210200321 |
5 | 311320024423 |
6 | 23455203121 |
7 | 3645003055 |
oct | 1140444071 |
9 | 363163254 |
10 | 159533113 |
11 | 82063653 |
12 | 455164a1 |
13 | 270890bc |
14 | 1728ac65 |
15 | e01410d |
hex | 9824839 |
159533113 has 2 divisors, whose sum is σ = 159533114. Its totient is φ = 159533112.
The previous prime is 159533111. The next prime is 159533119. The reversal of 159533113 is 311335951.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 158457744 + 1075369 = 12588^2 + 1037^2 .
It is an emirp because it is prime and its reverse (311335951) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 159533113 - 21 = 159533111 is a prime.
Together with 159533111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (159533111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 79766556 + 79766557.
It is an arithmetic number, because the mean of its divisors is an integer number (79766557).
Almost surely, 2159533113 is an apocalyptic number.
It is an amenable number.
159533113 is a deficient number, since it is larger than the sum of its proper divisors (1).
159533113 is an equidigital number, since it uses as much as digits as its factorization.
159533113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6075, while the sum is 31.
The square root of 159533113 is about 12630.6418285058. The cubic root of 159533113 is about 542.3549562337.
The spelling of 159533113 in words is "one hundred fifty-nine million, five hundred thirty-three thousand, one hundred thirteen".
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