Base | Representation |
---|---|
bin | 1001010010111100100… |
… | …1010000100010010101 |
3 | 120021020002122200211112 |
4 | 2110233021100202111 |
5 | 10104033403334013 |
6 | 201211202544405 |
7 | 14352426641522 |
oct | 2245711204225 |
9 | 507202580745 |
10 | 159704746133 |
11 | 618041905a9 |
12 | 26b50968105 |
13 | 120a20411aa |
14 | 7a30618149 |
15 | 424aab9ba8 |
hex | 252f250895 |
159704746133 has 2 divisors, whose sum is σ = 159704746134. Its totient is φ = 159704746132.
The previous prime is 159704746121. The next prime is 159704746153. The reversal of 159704746133 is 331647407951.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120786136849 + 38918609284 = 347543^2 + 197278^2 .
It is a cyclic number.
It is not a de Polignac number, because 159704746133 - 28 = 159704745877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (159704746153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 79852373066 + 79852373067.
It is an arithmetic number, because the mean of its divisors is an integer number (79852373067).
Almost surely, 2159704746133 is an apocalyptic number.
It is an amenable number.
159704746133 is a deficient number, since it is larger than the sum of its proper divisors (1).
159704746133 is an equidigital number, since it uses as much as digits as its factorization.
159704746133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1905120, while the sum is 50.
The spelling of 159704746133 in words is "one hundred fifty-nine billion, seven hundred four million, seven hundred forty-six thousand, one hundred thirty-three".
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