Base | Representation |
---|---|
bin | 11101110001000100… |
… | …10001000011111101 |
3 | 1112020201212110010012 |
4 | 32320202101003331 |
5 | 230212102024123 |
6 | 11201433553005 |
7 | 1104010226033 |
oct | 167042210375 |
9 | 45221773105 |
10 | 15980892413 |
11 | 6860885002 |
12 | 311bb75765 |
13 | 1678b26075 |
14 | ab85da553 |
15 | 637ebe378 |
hex | 3b88910fd |
15980892413 has 2 divisors, whose sum is σ = 15980892414. Its totient is φ = 15980892412.
The previous prime is 15980892401. The next prime is 15980892467. The reversal of 15980892413 is 31429808951.
15980892413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9551739289 + 6429153124 = 97733^2 + 80182^2 .
It is a cyclic number.
It is not a de Polignac number, because 15980892413 - 28 = 15980892157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15980892113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7990446206 + 7990446207.
It is an arithmetic number, because the mean of its divisors is an integer number (7990446207).
Almost surely, 215980892413 is an apocalyptic number.
It is an amenable number.
15980892413 is a deficient number, since it is larger than the sum of its proper divisors (1).
15980892413 is an equidigital number, since it uses as much as digits as its factorization.
15980892413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 50.
The spelling of 15980892413 in words is "fifteen billion, nine hundred eighty million, eight hundred ninety-two thousand, four hundred thirteen".
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