Base | Representation |
---|---|
bin | 1110100010110000111110… |
… | …1000001011001011010111 |
3 | 2002121200002020112101200021 |
4 | 3220230033220023023113 |
5 | 4043441342402322131 |
6 | 54001522223530011 |
7 | 3240161435362405 |
oct | 350541750131327 |
9 | 62550066471607 |
10 | 15990425432791 |
11 | 5105557318407 |
12 | 1963075159907 |
13 | 8bcb769a5624 |
14 | 3d3d254a0475 |
15 | 1cae33556e11 |
hex | e8b0fa0b2d7 |
15990425432791 has 2 divisors, whose sum is σ = 15990425432792. Its totient is φ = 15990425432790.
The previous prime is 15990425432749. The next prime is 15990425432803. The reversal of 15990425432791 is 19723452409951.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15990425432791 - 215 = 15990425400023 is a prime.
It is a super-3 number, since 3×159904254327913 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15990425532791) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7995212716395 + 7995212716396.
It is an arithmetic number, because the mean of its divisors is an integer number (7995212716396).
Almost surely, 215990425432791 is an apocalyptic number.
15990425432791 is a deficient number, since it is larger than the sum of its proper divisors (1).
15990425432791 is an equidigital number, since it uses as much as digits as its factorization.
15990425432791 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24494400, while the sum is 61.
The spelling of 15990425432791 in words is "fifteen trillion, nine hundred ninety billion, four hundred twenty-five million, four hundred thirty-two thousand, seven hundred ninety-one".
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