160114452055213 has 2 divisors, whose sum is σ = 160114452055214. Its totient is φ = 160114452055212.

The previous prime is 160114452055123. The next prime is 160114452055273. The reversal of 160114452055213 is 312550254411061.

Together with previous prime (160114452055123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114840757438884 + 45273694616329 = 10716378^2 + 6728573^2 .

It is an emirp because it is prime and its reverse (312550254411061) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 160114452055213 - 2²⁵ = 160114418500781 is a prime.

It is a super-2 number, since 2×160114452055213² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (160114452055273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80057226027606 + 80057226027607.

It is an arithmetic number, because the mean of its divisors is an integer number (80057226027607).

Almost surely, 2^{160114452055213} is an apocalyptic number.

It is an amenable number.

160114452055213 is a deficient number, since it is larger than the sum of its proper divisors (1).

160114452055213 is an equidigital number, since it uses as much as digits as its factorization.

160114452055213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 40.

The spelling of 160114452055213 in words is "one hundred sixty trillion, one hundred fourteen billion, four hundred fifty-two million, fifty-five thousand, two hundred thirteen".