Base | Representation |
---|---|
bin | 1110100101101100110100… |
… | …1011000111110010000011 |
3 | 2002210111020102111022121102 |
4 | 3221123031023013302003 |
5 | 4100303130113044003 |
6 | 54041022000045015 |
7 | 3243625135252541 |
oct | 351331513076203 |
9 | 62714212438542 |
10 | 16040850128003 |
11 | 5124982793238 |
12 | 19709a830376b |
13 | 8c485172219c |
14 | 3d654a382d91 |
15 | 1cc3d533c588 |
hex | e96cd2c7c83 |
16040850128003 has 2 divisors, whose sum is σ = 16040850128004. Its totient is φ = 16040850128002.
The previous prime is 16040850127999. The next prime is 16040850128033. The reversal of 16040850128003 is 30082105804061.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16040850128003 - 22 = 16040850127999 is a prime.
It is a super-2 number, since 2×160408501280032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16040850128033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8020425064001 + 8020425064002.
It is an arithmetic number, because the mean of its divisors is an integer number (8020425064002).
Almost surely, 216040850128003 is an apocalyptic number.
16040850128003 is a deficient number, since it is larger than the sum of its proper divisors (1).
16040850128003 is an equidigital number, since it uses as much as digits as its factorization.
16040850128003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 38.
The spelling of 16040850128003 in words is "sixteen trillion, forty billion, eight hundred fifty million, one hundred twenty-eight thousand, three".
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