16041383131 has 2 divisors, whose sum is σ = 16041383132. Its totient is φ = 16041383130.

The previous prime is 16041383129. The next prime is 16041383153. The reversal of 16041383131 is 13138314061.

16041383131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16041383131 - 2¹ = 16041383129 is a prime.

It is a super-2 number, since 2×16041383131² (a number of 21 digits) contains 22 as substring.

Together with 16041383129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 16041383093 and 16041383102.

It is not a weakly prime, because it can be changed into another prime (16041383161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8020691565 + 8020691566.

It is an arithmetic number, because the mean of its divisors is an integer number (8020691566).

Almost surely, 2^16041383131 is an apocalyptic number.

16041383131 is a deficient number, since it is larger than the sum of its proper divisors (1).

16041383131 is an equidigital number, since it uses as much as digits as its factorization.

16041383131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 16041383131 its reverse (13138314061), we get a palindrome (29179697192).

The spelling of 16041383131 in words is "sixteen billion, forty-one million, three hundred eighty-three thousand, one hundred thirty-one".