Base | Representation |
---|---|
bin | 1110100101110110000111… |
… | …0101110000110011101101 |
3 | 2002210201200020210010002120 |
4 | 3221131201311300303231 |
5 | 4100323232122142221 |
6 | 54042113255343153 |
7 | 3244044012540402 |
oct | 351354165606355 |
9 | 62721606703076 |
10 | 16043344334061 |
11 | 5125a4269a160 |
12 | 1971383681ab9 |
13 | 8c4b5b3a3365 |
14 | 3d67057262a9 |
15 | 1cc4ce2c15c6 |
hex | e9761d70ced |
16043344334061 has 32 divisors (see below), whose sum is σ = 23581016204928. Its totient is φ = 9621094256640.
The previous prime is 16043344334057. The next prime is 16043344334137.
16043344334061 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 16043344334061 - 22 = 16043344334057 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16043344334861) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15757881 + ... + 16745073.
It is an arithmetic number, because the mean of its divisors is an integer number (736906756404).
Almost surely, 216043344334061 is an apocalyptic number.
16043344334061 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
16043344334061 is a deficient number, since it is larger than the sum of its proper divisors (7537671870867).
16043344334061 is a wasteful number, since it uses less digits than its factorization.
16043344334061 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 992381.
The product of its (nonzero) digits is 746496, while the sum is 42.
It can be divided in two parts, 1604334 and 4334061, that added together give a palindrome (5938395).
The spelling of 16043344334061 in words is "sixteen trillion, forty-three billion, three hundred forty-four million, three hundred thirty-four thousand, sixty-one".
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