Base | Representation |
---|---|
bin | 101111110100001… |
… | …0011101101100001 |
3 | 11010210222001210221 |
4 | 1133220103231201 |
5 | 11241211331032 |
6 | 423111523041 |
7 | 54521122621 |
oct | 13750235541 |
9 | 4123861727 |
10 | 1604402017 |
11 | 753708a89 |
12 | 389389481 |
13 | 1c751760a |
14 | 11311c881 |
15 | 95cbd597 |
hex | 5fa13b61 |
1604402017 has 2 divisors, whose sum is σ = 1604402018. Its totient is φ = 1604402016.
The previous prime is 1604401999. The next prime is 1604402027. The reversal of 1604402017 is 7102044061.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1585313856 + 19088161 = 39816^2 + 4369^2 .
It is a cyclic number.
It is not a de Polignac number, because 1604402017 - 27 = 1604401889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1604401982 and 1604402000.
It is not a weakly prime, because it can be changed into another prime (1604402027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 802201008 + 802201009.
It is an arithmetic number, because the mean of its divisors is an integer number (802201009).
Almost surely, 21604402017 is an apocalyptic number.
It is an amenable number.
1604402017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1604402017 is an equidigital number, since it uses as much as digits as its factorization.
1604402017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
The square root of 1604402017 is about 40054.9874172992. The cubic root of 1604402017 is about 1170.6787444058.
Adding to 1604402017 its reverse (7102044061), we get a palindrome (8706446078).
The spelling of 1604402017 in words is "one billion, six hundred four million, four hundred two thousand, seventeen".
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