Base | Representation |
---|---|
bin | 1110100101111011100011… |
… | …0000011111100001100011 |
3 | 2002210212102212201012012121 |
4 | 3221132320300133201203 |
5 | 4100334223424222324 |
6 | 54042514110405111 |
7 | 3244125110413204 |
oct | 351367060374143 |
9 | 62725385635177 |
10 | 16044802570339 |
11 | 5126620844704 |
12 | 197170bb00797 |
13 | 8c503153206a |
14 | 3d68032775ab |
15 | 1cc56731b5e4 |
hex | e97b8c1f863 |
16044802570339 has 2 divisors, whose sum is σ = 16044802570340. Its totient is φ = 16044802570338.
The previous prime is 16044802570333. The next prime is 16044802570399. The reversal of 16044802570339 is 93307520844061.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16044802570339 is a prime.
It is not a weakly prime, because it can be changed into another prime (16044802570333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8022401285169 + 8022401285170.
It is an arithmetic number, because the mean of its divisors is an integer number (8022401285170).
It is a 2-persistent number, because it is pandigital, and so is 2⋅16044802570339 = 32089605140678, but 3⋅16044802570339 = 48134407711017 is not.
Almost surely, 216044802570339 is an apocalyptic number.
16044802570339 is a deficient number, since it is larger than the sum of its proper divisors (1).
16044802570339 is an equidigital number, since it uses as much as digits as its factorization.
16044802570339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4354560, while the sum is 52.
The spelling of 16044802570339 in words is "sixteen trillion, forty-four billion, eight hundred two million, five hundred seventy thousand, three hundred thirty-nine".
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