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16051120121 is a prime number
BaseRepresentation
bin11101111001011100…
…01010011111111001
31112102122000101102102
432330232022133321
5230333041320441
611212423113145
71105522161401
oct167456123771
945378011372
1016051120121
116897491133
12313b5a27b5
13168a54441a
14ac3a7b801
1563e24269b
hex3bcb8a7f9

16051120121 has 2 divisors, whose sum is σ = 16051120122. Its totient is φ = 16051120120.

The previous prime is 16051120117. The next prime is 16051120123. The reversal of 16051120121 is 12102115061.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14704230121 + 1346890000 = 121261^2 + 36700^2 .

It is a cyclic number.

It is not a de Polignac number, because 16051120121 - 22 = 16051120117 is a prime.

Together with 16051120123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 16051120093 and 16051120102.

It is not a weakly prime, because it can be changed into another prime (16051120123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8025560060 + 8025560061.

It is an arithmetic number, because the mean of its divisors is an integer number (8025560061).

Almost surely, 216051120121 is an apocalyptic number.

It is an amenable number.

16051120121 is a deficient number, since it is larger than the sum of its proper divisors (1).

16051120121 is an equidigital number, since it uses as much as digits as its factorization.

16051120121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 16051120121 its reverse (12102115061), we get a palindrome (28153235182).

The spelling of 16051120121 in words is "sixteen billion, fifty-one million, one hundred twenty thousand, one hundred twenty-one".