Base | Representation |
---|---|
bin | 11101111001100101… |
… | …10010111000100001 |
3 | 1112102201022001201002 |
4 | 32330302302320201 |
5 | 230333344142423 |
6 | 11212505121345 |
7 | 1105535405624 |
oct | 167462627041 |
9 | 45381261632 |
10 | 16052334113 |
11 | 6898140232 |
12 | 313ba89255 |
13 | 168a87ab6a |
14 | ac3cb5dbb |
15 | 63e3d2228 |
hex | 3bccb2e21 |
16052334113 has 2 divisors, whose sum is σ = 16052334114. Its totient is φ = 16052334112.
The previous prime is 16052334107. The next prime is 16052334121. The reversal of 16052334113 is 31143325061.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16052129809 + 204304 = 126697^2 + 452^2 .
It is an emirp because it is prime and its reverse (31143325061) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16052334113 - 24 = 16052334097 is a prime.
It is not a weakly prime, because it can be changed into another prime (16052334173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8026167056 + 8026167057.
It is an arithmetic number, because the mean of its divisors is an integer number (8026167057).
Almost surely, 216052334113 is an apocalyptic number.
It is an amenable number.
16052334113 is a deficient number, since it is larger than the sum of its proper divisors (1).
16052334113 is an equidigital number, since it uses as much as digits as its factorization.
16052334113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 16052334113 its reverse (31143325061), we get a palindrome (47195659174).
The spelling of 16052334113 in words is "sixteen billion, fifty-two million, three hundred thirty-four thousand, one hundred thirteen".
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