Base | Representation |
---|---|
bin | 1110100110111010010001… |
… | …1110010100100011000011 |
3 | 2002212110220110022112121121 |
4 | 3221232210132110203003 |
5 | 4101123220341203101 |
6 | 54054341100533111 |
7 | 3245262315340144 |
oct | 351564436244303 |
9 | 62773813275547 |
10 | 16061642131651 |
11 | 5132782291326 |
12 | 1974a2b551197 |
13 | 8c67b621011c |
14 | 3d755d911acb |
15 | 1ccc008a10a1 |
hex | e9ba47948c3 |
16061642131651 has 2 divisors, whose sum is σ = 16061642131652. Its totient is φ = 16061642131650.
The previous prime is 16061642131637. The next prime is 16061642131679. The reversal of 16061642131651 is 15613124616061.
It is a happy number.
16061642131651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16061642131651 - 215 = 16061642098883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16061642131598 and 16061642131607.
It is not a weakly prime, because it can be changed into another prime (16061642131681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8030821065825 + 8030821065826.
It is an arithmetic number, because the mean of its divisors is an integer number (8030821065826).
Almost surely, 216061642131651 is an apocalyptic number.
16061642131651 is a deficient number, since it is larger than the sum of its proper divisors (1).
16061642131651 is an equidigital number, since it uses as much as digits as its factorization.
16061642131651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 43.
The spelling of 16061642131651 in words is "sixteen trillion, sixty-one billion, six hundred forty-two million, one hundred thirty-one thousand, six hundred fifty-one".
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