Base | Representation |
---|---|
bin | 1110100110111010010001… |
… | …1110010101100000110011 |
3 | 2002212110220110022202000222 |
4 | 3221232210132111200303 |
5 | 4101123220341314403 |
6 | 54054341101003255 |
7 | 3245262315354521 |
oct | 351564436254063 |
9 | 62773813282028 |
10 | 16061642135603 |
11 | 5132782294299 |
12 | 1974a2b55352b |
13 | 8c67b6211b6c |
14 | 3d755d913311 |
15 | 1ccc008a2338 |
hex | e9ba4795833 |
16061642135603 has 2 divisors, whose sum is σ = 16061642135604. Its totient is φ = 16061642135602.
The previous prime is 16061642135597. The next prime is 16061642135647. The reversal of 16061642135603 is 30653124616061.
It is an a-pointer prime, because the next prime (16061642135647) can be obtained adding 16061642135603 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16061642135603 - 24 = 16061642135587 is a prime.
It is not a weakly prime, because it can be changed into another prime (16061647135603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8030821067801 + 8030821067802.
It is an arithmetic number, because the mean of its divisors is an integer number (8030821067802).
Almost surely, 216061642135603 is an apocalyptic number.
16061642135603 is a deficient number, since it is larger than the sum of its proper divisors (1).
16061642135603 is an equidigital number, since it uses as much as digits as its factorization.
16061642135603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 44.
The spelling of 16061642135603 in words is "sixteen trillion, sixty-one billion, six hundred forty-two million, one hundred thirty-five thousand, six hundred three".
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