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1606221300413 is a prime number
BaseRepresentation
bin10111010111111010010…
…000000000001010111101
312200112221022202021202002
4113113322100000022331
5202304020123103123
63225515440512045
7224021442533102
oct27277220001275
95615838667662
101606221300413
1156a216060584
1221b36831b625
13b8609ac63a2
1457a54a64aa9
152bbac882528
hex175fa4002bd

1606221300413 has 2 divisors, whose sum is σ = 1606221300414. Its totient is φ = 1606221300412.

The previous prime is 1606221300391. The next prime is 1606221300427. The reversal of 1606221300413 is 3140031226061.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1597804705849 + 8416594564 = 1264043^2 + 91742^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1606221300413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1606221300473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 803110650206 + 803110650207.

It is an arithmetic number, because the mean of its divisors is an integer number (803110650207).

Almost surely, 21606221300413 is an apocalyptic number.

It is an amenable number.

1606221300413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1606221300413 is an equidigital number, since it uses as much as digits as its factorization.

1606221300413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1606221300413 its reverse (3140031226061), we get a palindrome (4746252526474).

The spelling of 1606221300413 in words is "one trillion, six hundred six billion, two hundred twenty-one million, three hundred thousand, four hundred thirteen".