Base | Representation |
---|---|
bin | 1110100111000110101011… |
… | …0101101110110000110111 |
3 | 2002212210111101120202021211 |
4 | 3221301222311232300313 |
5 | 4101202024330011421 |
6 | 54100051224022251 |
7 | 3245440636155241 |
oct | 351615265566067 |
9 | 62783441522254 |
10 | 16064970157111 |
11 | 513412a928097 |
12 | 19755ba001987 |
13 | 8c6bc6855765 |
14 | 3d7797905091 |
15 | 1ccd47b3c9e1 |
hex | e9c6ad6ec37 |
16064970157111 has 2 divisors, whose sum is σ = 16064970157112. Its totient is φ = 16064970157110.
The previous prime is 16064970157043. The next prime is 16064970157141. The reversal of 16064970157111 is 11175107946061.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16064970157111 - 223 = 16064961768503 is a prime.
It is a super-2 number, since 2×160649701571112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16064970157141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8032485078555 + 8032485078556.
It is an arithmetic number, because the mean of its divisors is an integer number (8032485078556).
Almost surely, 216064970157111 is an apocalyptic number.
16064970157111 is a deficient number, since it is larger than the sum of its proper divisors (1).
16064970157111 is an equidigital number, since it uses as much as digits as its factorization.
16064970157111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 317520, while the sum is 49.
The spelling of 16064970157111 in words is "sixteen trillion, sixty-four billion, nine hundred seventy million, one hundred fifty-seven thousand, one hundred eleven".
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