Base | Representation |
---|---|
bin | 10111011000110010001… |
… | …001111011011110010001 |
3 | 12200122100200122011112212 |
4 | 113120302021323132101 |
5 | 202312430230414101 |
6 | 3230152504001505 |
7 | 224053622034512 |
oct | 27306211733621 |
9 | 5618320564485 |
10 | 1607159232401 |
11 | 56a657540788 |
12 | 21b58a460295 |
13 | b8729211228 |
14 | 57b03456a09 |
15 | 2bc14da31bb |
hex | 1763227b791 |
1607159232401 has 2 divisors, whose sum is σ = 1607159232402. Its totient is φ = 1607159232400.
The previous prime is 1607159232391. The next prime is 1607159232403. The reversal of 1607159232401 is 1042329517061.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1230433344001 + 376725888400 = 1109249^2 + 613780^2 .
It is a cyclic number.
It is not a de Polignac number, because 1607159232401 - 214 = 1607159216017 is a prime.
Together with 1607159232403, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1607159232403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 803579616200 + 803579616201.
It is an arithmetic number, because the mean of its divisors is an integer number (803579616201).
Almost surely, 21607159232401 is an apocalyptic number.
It is an amenable number.
1607159232401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1607159232401 is an equidigital number, since it uses as much as digits as its factorization.
1607159232401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 41.
The spelling of 1607159232401 in words is "one trillion, six hundred seven billion, one hundred fifty-nine million, two hundred thirty-two thousand, four hundred one".
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