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16095815423957 is a prime number
BaseRepresentation
bin1110101000111001100101…
…0111000101011111010101
32002222202010001101122210102
43222032121113011133111
54102203212222031312
654122152053103445
73250612211463023
oct352163127053725
962882101348712
1016095815423957
11514621920a665
12197b588027b85
138c9aa108c649
143d90822dd713
151cda50a80ec2
hexea3995c57d5

16095815423957 has 2 divisors, whose sum is σ = 16095815423958. Its totient is φ = 16095815423956.

The previous prime is 16095815423903. The next prime is 16095815424067. The reversal of 16095815423957 is 75932451859061.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15722501755921 + 373313668036 = 3965161^2 + 610994^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16095815423957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16095815423893 and 16095815423902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16095815423357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8047907711978 + 8047907711979.

It is an arithmetic number, because the mean of its divisors is an integer number (8047907711979).

It is a 1-persistent number, because it is pandigital, but 2⋅16095815423957 = 32191630847914 is not.

Almost surely, 216095815423957 is an apocalyptic number.

It is an amenable number.

16095815423957 is a deficient number, since it is larger than the sum of its proper divisors (1).

16095815423957 is an equidigital number, since it uses as much as digits as its factorization.

16095815423957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648000, while the sum is 65.

The spelling of 16095815423957 in words is "sixteen trillion, ninety-five billion, eight hundred fifteen million, four hundred twenty-three thousand, nine hundred fifty-seven".