Base | Representation |
---|---|
bin | 1110101001010001000100… |
… | …1101100110100001001111 |
3 | 2010000100101111202210121001 |
4 | 3222110101031212201033 |
5 | 4102304121004433043 |
6 | 54125113511121131 |
7 | 3251224400445166 |
oct | 352242115464117 |
9 | 63010344683531 |
10 | 16102121171023 |
11 | 514896468a778 |
12 | 19808479731a7 |
13 | 8ca5675b9024 |
14 | 3d94bd97a3dd |
15 | 1cdcbe46074d |
hex | ea51136684f |
16102121171023 has 2 divisors, whose sum is σ = 16102121171024. Its totient is φ = 16102121171022.
The previous prime is 16102121170999. The next prime is 16102121171063. The reversal of 16102121171023 is 32017112120161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16102121171023 - 221 = 16102119073871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16102121170982 and 16102121171000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16102121171063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8051060585511 + 8051060585512.
It is an arithmetic number, because the mean of its divisors is an integer number (8051060585512).
Almost surely, 216102121171023 is an apocalyptic number.
16102121171023 is a deficient number, since it is larger than the sum of its proper divisors (1).
16102121171023 is an equidigital number, since it uses as much as digits as its factorization.
16102121171023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 28.
Adding to 16102121171023 its reverse (32017112120161), we get a palindrome (48119233291184).
The spelling of 16102121171023 in words is "sixteen trillion, one hundred two billion, one hundred twenty-one million, one hundred seventy-one thousand, twenty-three".
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