Base | Representation |
---|---|
bin | 1110101001010001100001… |
… | …1111101100011001011111 |
3 | 2010000100201000200100102011 |
4 | 3222110120133230121133 |
5 | 4102304343244313312 |
6 | 54125133554012051 |
7 | 3251230413131323 |
oct | 352243037543137 |
9 | 63010630610364 |
10 | 16102243354207 |
11 | 5148a1765280a |
12 | 1980880877027 |
13 | 8ca5869c887a |
14 | 3d94d1ca3983 |
15 | 1cdcca047da7 |
hex | ea5187ec65f |
16102243354207 has 2 divisors, whose sum is σ = 16102243354208. Its totient is φ = 16102243354206.
The previous prime is 16102243354201. The next prime is 16102243354271. The reversal of 16102243354207 is 70245334220161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16102243354207 - 27 = 16102243354079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16102243354207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16102243354201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8051121677103 + 8051121677104.
It is an arithmetic number, because the mean of its divisors is an integer number (8051121677104).
Almost surely, 216102243354207 is an apocalyptic number.
16102243354207 is a deficient number, since it is larger than the sum of its proper divisors (1).
16102243354207 is an equidigital number, since it uses as much as digits as its factorization.
16102243354207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 16102243354207 its reverse (70245334220161), we get a palindrome (86347577574368).
The spelling of 16102243354207 in words is "sixteen trillion, one hundred two billion, two hundred forty-three million, three hundred fifty-four thousand, two hundred seven".
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