Base | Representation |
---|---|
bin | 1110101001111110110111… |
… | …0001101001111001000011 |
3 | 2010001112010001021102222001 |
4 | 3222133231301221321003 |
5 | 4103004303323403011 |
6 | 54134505232324431 |
7 | 3252141066054565 |
oct | 352375561517103 |
9 | 63045101242861 |
10 | 16114411544131 |
11 | 51530a123aa1a |
12 | 19830b79a3717 |
13 | 8cb77595a854 |
14 | 3d9d27d83335 |
15 | 1ce28d43c7c1 |
hex | ea7edc69e43 |
16114411544131 has 2 divisors, whose sum is σ = 16114411544132. Its totient is φ = 16114411544130.
The previous prime is 16114411544113. The next prime is 16114411544207. The reversal of 16114411544131 is 13144511441161.
Together with previous prime (16114411544113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16114411544131 - 239 = 15564655730243 is a prime.
It is a super-2 number, since 2×161144115441312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16114411544431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8057205772065 + 8057205772066.
It is an arithmetic number, because the mean of its divisors is an integer number (8057205772066).
Almost surely, 216114411544131 is an apocalyptic number.
16114411544131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16114411544131 is an equidigital number, since it uses as much as digits as its factorization.
16114411544131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23040, while the sum is 37.
Adding to 16114411544131 its reverse (13144511441161), we get a palindrome (29258922985292).
The spelling of 16114411544131 in words is "sixteen trillion, one hundred fourteen billion, four hundred eleven million, five hundred forty-four thousand, one hundred thirty-one".
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