Base | Representation |
---|---|
bin | 1110101001111110110111… |
… | …0001101001111101101111 |
3 | 2010001112010001021110101011 |
4 | 3222133231301221331233 |
5 | 4103004303323410211 |
6 | 54134505232330051 |
7 | 3252141066055504 |
oct | 352375561517557 |
9 | 63045101243334 |
10 | 16114411544431 |
11 | 51530a1240172 |
12 | 19830b79a3927 |
13 | 8cb77595aa25 |
14 | 3d9d27d834ab |
15 | 1ce28d43c921 |
hex | ea7edc69f6f |
16114411544431 has 2 divisors, whose sum is σ = 16114411544432. Its totient is φ = 16114411544430.
The previous prime is 16114411544411. The next prime is 16114411544437. The reversal of 16114411544431 is 13444511441161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16114411544431 - 27 = 16114411544303 is a prime.
It is a super-2 number, since 2×161144115444312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16114411544437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8057205772215 + 8057205772216.
It is an arithmetic number, because the mean of its divisors is an integer number (8057205772216).
Almost surely, 216114411544431 is an apocalyptic number.
16114411544431 is a deficient number, since it is larger than the sum of its proper divisors (1).
16114411544431 is an equidigital number, since it uses as much as digits as its factorization.
16114411544431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 92160, while the sum is 40.
Adding to 16114411544431 its reverse (13444511441161), we get a palindrome (29558922985592).
The spelling of 16114411544431 in words is "sixteen trillion, one hundred fourteen billion, four hundred eleven million, five hundred forty-four thousand, four hundred thirty-one".
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