Search a number
-
+
16120760413 is a prime number
BaseRepresentation
bin11110000001101111…
…10100100001011101
31112121111001110221111
433000313310201131
5231003403313123
611223351502021
71110326126332
oct170067644135
945544043844
1016120760413
11692282699a
12315a987911
13169bab82b4
14acd008989
156453eb90d
hex3c0df485d

16120760413 has 2 divisors, whose sum is σ = 16120760414. Its totient is φ = 16120760412.

The previous prime is 16120760401. The next prime is 16120760431. The reversal of 16120760413 is 31406702161.

Together with next prime (16120760431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13155631204 + 2965129209 = 114698^2 + 54453^2 .

It is an emirp because it is prime and its reverse (31406702161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16120760413 - 217 = 16120629341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16120760443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8060380206 + 8060380207.

It is an arithmetic number, because the mean of its divisors is an integer number (8060380207).

Almost surely, 216120760413 is an apocalyptic number.

It is an amenable number.

16120760413 is a deficient number, since it is larger than the sum of its proper divisors (1).

16120760413 is an equidigital number, since it uses as much as digits as its factorization.

16120760413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

The spelling of 16120760413 in words is "sixteen billion, one hundred twenty million, seven hundred sixty thousand, four hundred thirteen".