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161224115441 is a prime number
BaseRepresentation
bin1001011000100110110…
…1001100010011110001
3120102010222121122200212
42112021231030103301
510120141333143231
6202022040153505
714435166240614
oct2261155142361
9512128548625
10161224115441
11624138a0214
12272b5768895
1312284a5579c
147b3632017b
1542d918d42b
hex2589b4c4f1

161224115441 has 2 divisors, whose sum is σ = 161224115442. Its totient is φ = 161224115440.

The previous prime is 161224115431. The next prime is 161224115467. The reversal of 161224115441 is 144511422161.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 157387551841 + 3836563600 = 396721^2 + 61940^2 .

It is an emirp because it is prime and its reverse (144511422161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 161224115441 - 234 = 144044246257 is a prime.

It is a super-3 number, since 3×1612241154413 (a number of 35 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 161224115398 and 161224115407.

It is not a weakly prime, because it can be changed into another prime (161224115431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80612057720 + 80612057721.

It is an arithmetic number, because the mean of its divisors is an integer number (80612057721).

Almost surely, 2161224115441 is an apocalyptic number.

It is an amenable number.

161224115441 is a deficient number, since it is larger than the sum of its proper divisors (1).

161224115441 is an equidigital number, since it uses as much as digits as its factorization.

161224115441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7680, while the sum is 32.

The spelling of 161224115441 in words is "one hundred sixty-one billion, two hundred twenty-four million, one hundred fifteen thousand, four hundred forty-one".