Base | Representation |
---|---|
bin | 1110101010100100000010… |
… | …1010110110100000111111 |
3 | 2010002110212121122111220021 |
4 | 3222221000222312200333 |
5 | 4103140223401014401 |
6 | 54143235444433011 |
7 | 3252643320220414 |
oct | 352510052664077 |
9 | 63073777574807 |
10 | 16124392204351 |
11 | 5157353045742 |
12 | 19850223a8767 |
13 | 8cc6a6636262 |
14 | 3da5d371010b |
15 | 1ce67477a2a1 |
hex | eaa40ab683f |
16124392204351 has 2 divisors, whose sum is σ = 16124392204352. Its totient is φ = 16124392204350.
The previous prime is 16124392204247. The next prime is 16124392204373. The reversal of 16124392204351 is 15340229342161.
16124392204351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16124392204351 - 27 = 16124392204223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16124392204298 and 16124392204307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16124392204451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8062196102175 + 8062196102176.
It is an arithmetic number, because the mean of its divisors is an integer number (8062196102176).
Almost surely, 216124392204351 is an apocalyptic number.
16124392204351 is a deficient number, since it is larger than the sum of its proper divisors (1).
16124392204351 is an equidigital number, since it uses as much as digits as its factorization.
16124392204351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 16124392204351 in words is "sixteen trillion, one hundred twenty-four billion, three hundred ninety-two million, two hundred four thousand, three hundred fifty-one".
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