Base | Representation |
---|---|
bin | 11110000010010001… |
… | …00001110011100101 |
3 | 1112121210021222212201 |
4 | 33001020201303211 |
5 | 231011013441242 |
6 | 11224025414501 |
7 | 1110411300355 |
oct | 170110416345 |
9 | 45553258781 |
10 | 16125140197 |
11 | 6925248551 |
12 | 316033a431 |
13 | 169c98c99a |
14 | acd828b65 |
15 | 6459b44b7 |
hex | 3c1221ce5 |
16125140197 has 2 divisors, whose sum is σ = 16125140198. Its totient is φ = 16125140196.
The previous prime is 16125140179. The next prime is 16125140201. The reversal of 16125140197 is 79104152161.
Together with previous prime (16125140179) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12633984801 + 3491155396 = 112401^2 + 59086^2 .
It is a cyclic number.
It is not a de Polignac number, because 16125140197 - 223 = 16116751589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16125140117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8062570098 + 8062570099.
It is an arithmetic number, because the mean of its divisors is an integer number (8062570099).
Almost surely, 216125140197 is an apocalyptic number.
It is an amenable number.
16125140197 is a deficient number, since it is larger than the sum of its proper divisors (1).
16125140197 is an equidigital number, since it uses as much as digits as its factorization.
16125140197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 37.
The spelling of 16125140197 in words is "sixteen billion, one hundred twenty-five million, one hundred forty thousand, one hundred ninety-seven".
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