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161255015265353 is a prime number
BaseRepresentation
bin100100101010100100011011…
…111001110011010001001001
3210010221211101021100012112212
4210222210123321303101021
5132114000232401442403
61330543310433514505
745652201414053452
oct4452443371632111
9703854337305485
10161255015265353
1147420960231519
1216104376412a35
136bc938a0c3a89
142bb6ada4ba129
15139992dd724d8
hex92a91be73449

161255015265353 has 2 divisors, whose sum is σ = 161255015265354. Its totient is φ = 161255015265352.

The previous prime is 161255015265347. The next prime is 161255015265391. The reversal of 161255015265353 is 353562510552161.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137521778473024 + 23733236792329 = 11726968^2 + 4871677^2 .

It is a cyclic number.

It is not a de Polignac number, because 161255015265353 - 230 = 161253941523529 is a prime.

It is a super-2 number, since 2×1612550152653532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (161255014265353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80627507632676 + 80627507632677.

It is an arithmetic number, because the mean of its divisors is an integer number (80627507632677).

Almost surely, 2161255015265353 is an apocalyptic number.

It is an amenable number.

161255015265353 is a deficient number, since it is larger than the sum of its proper divisors (1).

161255015265353 is an equidigital number, since it uses as much as digits as its factorization.

161255015265353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050000, while the sum is 50.

The spelling of 161255015265353 in words is "one hundred sixty-one trillion, two hundred fifty-five billion, fifteen million, two hundred sixty-five thousand, three hundred fifty-three".