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16130263353041 is a prime number
BaseRepresentation
bin1110101010111001111010…
…0111100000011011010001
32010010001000210020202210202
43222232132213200123101
54103234234404244131
654150050215504545
73253241651161115
oct352563647403321
963101023222722
1016130263353041
115159896169642
1219861a0688155
13900100ac9336
143da9cd37b745
151ce8b9e0ebcb
hexeab9e9e06d1

16130263353041 has 2 divisors, whose sum is σ = 16130263353042. Its totient is φ = 16130263353040.

The previous prime is 16130263353007. The next prime is 16130263353047. The reversal of 16130263353041 is 14035336203161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10074726713041 + 6055536640000 = 3174071^2 + 2460800^2 .

It is a cyclic number.

It is not a de Polignac number, because 16130263353041 - 210 = 16130263352017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16130263352986 and 16130263353004.

It is not a weakly prime, because it can be changed into another prime (16130263353047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8065131676520 + 8065131676521.

It is an arithmetic number, because the mean of its divisors is an integer number (8065131676521).

Almost surely, 216130263353041 is an apocalyptic number.

It is an amenable number.

16130263353041 is a deficient number, since it is larger than the sum of its proper divisors (1).

16130263353041 is an equidigital number, since it uses as much as digits as its factorization.

16130263353041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 38.

The spelling of 16130263353041 in words is "sixteen trillion, one hundred thirty billion, two hundred sixty-three million, three hundred fifty-three thousand, forty-one".