Base | Representation |
---|---|
bin | 1110101011001011011110… |
… | …0110000100101101110101 |
3 | 2010010111012022111220101002 |
4 | 3222302313212010231311 |
5 | 4103323413202000333 |
6 | 54152150053413045 |
7 | 3253466531536463 |
oct | 352626746045565 |
9 | 63114168456332 |
10 | 16134977375093 |
11 | 51608950aa135 |
12 | 198709733a185 |
13 | 9006a26295b5 |
14 | 3dad19479833 |
15 | 1cea93bc70e8 |
hex | eacb7984b75 |
16134977375093 has 2 divisors, whose sum is σ = 16134977375094. Its totient is φ = 16134977375092.
The previous prime is 16134977375071. The next prime is 16134977375147. The reversal of 16134977375093 is 39057377943161.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14037326276164 + 2097651098929 = 3746642^2 + 1448327^2 .
It is a cyclic number.
It is not a de Polignac number, because 16134977375093 - 226 = 16134910266229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16134977372093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8067488687546 + 8067488687547.
It is an arithmetic number, because the mean of its divisors is an integer number (8067488687547).
Almost surely, 216134977375093 is an apocalyptic number.
It is an amenable number.
16134977375093 is a deficient number, since it is larger than the sum of its proper divisors (1).
16134977375093 is an equidigital number, since it uses as much as digits as its factorization.
16134977375093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90016920, while the sum is 65.
The spelling of 16134977375093 in words is "sixteen trillion, one hundred thirty-four billion, nine hundred seventy-seven million, three hundred seventy-five thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.793 sec. • engine limits •