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16140413627797 is a prime number
BaseRepresentation
bin1110101011011111101110…
…0111101110110110010101
32010011000020011210011010211
43222313323213232312111
54103421031342042142
654154445331245421
73254051332115644
oct352677347566625
963130204704124
1016140413627797
115163124793268
121988153a49871
1390105a980784
143db2b345b35b
151cecb10a3917
hexeadfb9eed95

16140413627797 has 2 divisors, whose sum is σ = 16140413627798. Its totient is φ = 16140413627796.

The previous prime is 16140413627761. The next prime is 16140413627803. The reversal of 16140413627797 is 79772631404161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15742159234321 + 398254393476 = 3967639^2 + 631074^2 .

It is a cyclic number.

It is not a de Polignac number, because 16140413627797 - 227 = 16140279410069 is a prime.

It is a super-2 number, since 2×161404136277972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16140413625797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8070206813898 + 8070206813899.

It is an arithmetic number, because the mean of its divisors is an integer number (8070206813899).

Almost surely, 216140413627797 is an apocalyptic number.

It is an amenable number.

16140413627797 is a deficient number, since it is larger than the sum of its proper divisors (1).

16140413627797 is an equidigital number, since it uses as much as digits as its factorization.

16140413627797 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10668672, while the sum is 58.

The spelling of 16140413627797 in words is "sixteen trillion, one hundred forty billion, four hundred thirteen million, six hundred twenty-seven thousand, seven hundred ninety-seven".