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1614302031161 is a prime number
BaseRepresentation
bin10111011111011011111…
…001100010110100111001
312201022210111001221102002
4113133123321202310321
5202422042304444121
63233333342550345
7224425623601631
oct27373371426471
95638714057362
101614302031161
11572692459156
12220a425983b5
13b92c6c94381
14581bdd456c1
152bed1ec7e0b
hex177dbe62d39

1614302031161 has 2 divisors, whose sum is σ = 1614302031162. Its totient is φ = 1614302031160.

The previous prime is 1614302031137. The next prime is 1614302031163. The reversal of 1614302031161 is 1611302034161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1611835915561 + 2466115600 = 1269581^2 + 49660^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1614302031161 is a prime.

Together with 1614302031163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1614302031163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 807151015580 + 807151015581.

It is an arithmetic number, because the mean of its divisors is an integer number (807151015581).

Almost surely, 21614302031161 is an apocalyptic number.

It is an amenable number.

1614302031161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1614302031161 is an equidigital number, since it uses as much as digits as its factorization.

1614302031161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 1614302031161 in words is "one trillion, six hundred fourteen billion, three hundred two million, thirty-one thousand, one hundred sixty-one".