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161462022133 is a prime number
BaseRepresentation
bin1001011001011111100…
…0101110111111110101
3120102202120021120022211
42112113320232333311
510121133234202013
6202101415253421
714444115354256
oct2262770567765
9512676246284
10161462022133
1162526114015
122736137a271
13122c2122889
147b59b6cb2d
1542eeed423d
hex2597e2eff5

161462022133 has 2 divisors, whose sum is σ = 161462022134. Its totient is φ = 161462022132.

The previous prime is 161462022031. The next prime is 161462022157. The reversal of 161462022133 is 331220264161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 158640500209 + 2821521924 = 398297^2 + 53118^2 .

It is a cyclic number.

It is not a de Polignac number, because 161462022133 - 217 = 161461891061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 161462022095 and 161462022104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (161462022233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80731011066 + 80731011067.

It is an arithmetic number, because the mean of its divisors is an integer number (80731011067).

Almost surely, 2161462022133 is an apocalyptic number.

It is an amenable number.

161462022133 is a deficient number, since it is larger than the sum of its proper divisors (1).

161462022133 is an equidigital number, since it uses as much as digits as its factorization.

161462022133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 161462022133 its reverse (331220264161), we get a palindrome (492682286294).

The spelling of 161462022133 in words is "one hundred sixty-one billion, four hundred sixty-two million, twenty-two thousand, one hundred thirty-three".