Base | Representation |
---|---|
bin | 1110101100010111101111… |
… | …0111000100011110110111 |
3 | 2010012110001002102201220002 |
4 | 3223011323313010132313 |
5 | 4104142330202042403 |
6 | 54205413345501515 |
7 | 3255123053345132 |
oct | 353057367043667 |
9 | 63173032381802 |
10 | 16155450034103 |
11 | 5169540410936 |
12 | 198b04b64189b |
13 | 9025b5c05703 |
14 | 3dbcdc43b219 |
15 | 1d03911aa188 |
hex | eb17bdc47b7 |
16155450034103 has 4 divisors (see below), whose sum is σ = 16499183013600. Its totient is φ = 15811717054608.
The previous prime is 16155450034079. The next prime is 16155450034111. The reversal of 16155450034103 is 30143005455161.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16155450034103 - 212 = 16155450030007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16155450034123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171866489678 + ... + 171866489771.
It is an arithmetic number, because the mean of its divisors is an integer number (4124795753400).
Almost surely, 216155450034103 is an apocalyptic number.
16155450034103 is a deficient number, since it is larger than the sum of its proper divisors (343732979497).
16155450034103 is an equidigital number, since it uses as much as digits as its factorization.
16155450034103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343732979496.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 16155450034103 its reverse (30143005455161), we get a palindrome (46298455489264).
The spelling of 16155450034103 in words is "sixteen trillion, one hundred fifty-five billion, four hundred fifty million, thirty-four thousand, one hundred three".
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