Base | Representation |
---|---|
bin | 1110101111110011000001… |
… | …0010101001011011000111 |
3 | 2010102001222021010001121111 |
4 | 3223330300102221123013 |
5 | 4111123402301041111 |
6 | 54252430232225451 |
7 | 3262305521513362 |
oct | 353746022513307 |
9 | 63361867101544 |
10 | 16214311737031 |
11 | 51914a62a6511 |
12 | 199a53823b287 |
13 | 908006893525 |
14 | 400ac3a630d9 |
15 | 1d1b88a0ea21 |
hex | ebf304a96c7 |
16214311737031 has 2 divisors, whose sum is σ = 16214311737032. Its totient is φ = 16214311737030.
The previous prime is 16214311736989. The next prime is 16214311737067. The reversal of 16214311737031 is 13073711341261.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16214311737031 - 215 = 16214311704263 is a prime.
It is a super-2 number, since 2×162143117370312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16214311737431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8107155868515 + 8107155868516.
It is an arithmetic number, because the mean of its divisors is an integer number (8107155868516).
Almost surely, 216214311737031 is an apocalyptic number.
16214311737031 is a deficient number, since it is larger than the sum of its proper divisors (1).
16214311737031 is an equidigital number, since it uses as much as digits as its factorization.
16214311737031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 40.
The spelling of 16214311737031 in words is "sixteen trillion, two hundred fourteen billion, three hundred eleven million, seven hundred thirty-seven thousand, thirty-one".
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