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162302543131397 is a prime number
BaseRepresentation
bin100100111001110100000001…
…011011011111001100000101
3210021122222020021211101101212
4210321310001123133030011
5132233131102020201042
61333104431535301205
746120654215026564
oct4471640133371405
9707588207741355
10162302543131397
1147795138419649
12162533a137a805
136c740aac08776
142c116b0bb7bdb
1513b6cdce09482
hex939d016df305

162302543131397 has 2 divisors, whose sum is σ = 162302543131398. Its totient is φ = 162302543131396.

The previous prime is 162302543131343. The next prime is 162302543131411. The reversal of 162302543131397 is 793131345203261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131026162515556 + 31276380615841 = 11446666^2 + 5592529^2 .

It is a cyclic number.

It is not a de Polignac number, because 162302543131397 - 222 = 162302538937093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (162302543131997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81151271565698 + 81151271565699.

It is an arithmetic number, because the mean of its divisors is an integer number (81151271565699).

Almost surely, 2162302543131397 is an apocalyptic number.

It is an amenable number.

162302543131397 is a deficient number, since it is larger than the sum of its proper divisors (1).

162302543131397 is an equidigital number, since it uses as much as digits as its factorization.

162302543131397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2449440, while the sum is 50.

The spelling of 162302543131397 in words is "one hundred sixty-two trillion, three hundred two billion, five hundred forty-three million, one hundred thirty-one thousand, three hundred ninety-seven".