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1623083161361 is a prime number
BaseRepresentation
bin10111100111100111010…
…010111001011100010001
312202011110110022120111112
4113213213102321130101
5203043033242130421
63241344545023105
7225156341144414
oct27474722713421
95664413276445
101623083161361
11576389149252
12222693324a95
13ba0962b14bc
14587b4265b7b
152c347d6e45b
hex179e74b9711

1623083161361 has 2 divisors, whose sum is σ = 1623083161362. Its totient is φ = 1623083161360.

The previous prime is 1623083161327. The next prime is 1623083161363. The reversal of 1623083161361 is 1631613803261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1321478997136 + 301604164225 = 1149556^2 + 549185^2 .

It is a cyclic number.

It is not a de Polignac number, because 1623083161361 - 210 = 1623083160337 is a prime.

Together with 1623083161363, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1623083161363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 811541580680 + 811541580681.

It is an arithmetic number, because the mean of its divisors is an integer number (811541580681).

Almost surely, 21623083161361 is an apocalyptic number.

It is an amenable number.

1623083161361 is a deficient number, since it is larger than the sum of its proper divisors (1).

1623083161361 is an equidigital number, since it uses as much as digits as its factorization.

1623083161361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 1623083161361 in words is "one trillion, six hundred twenty-three billion, eighty-three million, one hundred sixty-one thousand, three hundred sixty-one".