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16233140041 is a prime number
BaseRepresentation
bin11110001111001001…
…00000111101001001
31112220022111221210221
433013210200331021
5231221140440131
611242444310041
71113162261616
oct170744407511
945808457727
1016233140041
116980203418
123190542321
1316b9174811
14addcdd50d
156501e9411
hex3c7920f49

16233140041 has 2 divisors, whose sum is σ = 16233140042. Its totient is φ = 16233140040.

The previous prime is 16233139997. The next prime is 16233140069. The reversal of 16233140041 is 14004133261.

16233140041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16130016016 + 103124025 = 127004^2 + 10155^2 .

It is a cyclic number.

It is not a de Polignac number, because 16233140041 - 29 = 16233139529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16233139988 and 16233140015.

It is not a weakly prime, because it can be changed into another prime (16233143041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8116570020 + 8116570021.

It is an arithmetic number, because the mean of its divisors is an integer number (8116570021).

Almost surely, 216233140041 is an apocalyptic number.

It is an amenable number.

16233140041 is a deficient number, since it is larger than the sum of its proper divisors (1).

16233140041 is an equidigital number, since it uses as much as digits as its factorization.

16233140041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 16233140041 in words is "sixteen billion, two hundred thirty-three million, one hundred forty thousand, forty-one".