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16241208881 is a prime number
BaseRepresentation
bin11110010000000110…
…10010111000110001
31112220212200220011212
433020003102320301
5231230222141011
611243333245505
71113320666132
oct171003227061
945825626155
1016241208881
116984814687
123193193895
1316baa3b391
14b00dddc89
15650c9008b
hex3c80d2e31

16241208881 has 2 divisors, whose sum is σ = 16241208882. Its totient is φ = 16241208880.

The previous prime is 16241208821. The next prime is 16241208883. The reversal of 16241208881 is 18880214261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16241208481 + 400 = 127441^2 + 20^2 .

It is a cyclic number.

It is not a de Polignac number, because 16241208881 - 226 = 16174100017 is a prime.

It is a super-2 number, since 2×162412088812 (a number of 21 digits) contains 22 as substring.

Together with 16241208883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16241208883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8120604440 + 8120604441.

It is an arithmetic number, because the mean of its divisors is an integer number (8120604441).

Almost surely, 216241208881 is an apocalyptic number.

It is an amenable number.

16241208881 is a deficient number, since it is larger than the sum of its proper divisors (1).

16241208881 is an equidigital number, since it uses as much as digits as its factorization.

16241208881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49152, while the sum is 41.

The spelling of 16241208881 in words is "sixteen billion, two hundred forty-one million, two hundred eight thousand, eight hundred eighty-one".