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1625068309693 is a prime number
BaseRepresentation
bin10111101001011101100…
…111101000110010111101
312202100120210201120001211
4113221131213220302331
5203111114441402233
63242313541404421
7225256464502033
oct27513547506275
95670523646054
101625068309693
11577207771604
12222b48109711
13ba32165889a
1458921b76553
152c41229b5cd
hex17a5d9e8cbd

1625068309693 has 2 divisors, whose sum is σ = 1625068309694. Its totient is φ = 1625068309692.

The previous prime is 1625068309643. The next prime is 1625068309729. The reversal of 1625068309693 is 3969038605261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1522269842809 + 102798466884 = 1233803^2 + 320622^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1625068309693 is a prime.

It is a super-2 number, since 2×16250683096932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1625068309603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 812534154846 + 812534154847.

It is an arithmetic number, because the mean of its divisors is an integer number (812534154847).

Almost surely, 21625068309693 is an apocalyptic number.

It is an amenable number.

1625068309693 is a deficient number, since it is larger than the sum of its proper divisors (1).

1625068309693 is an equidigital number, since it uses as much as digits as its factorization.

1625068309693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12597120, while the sum is 58.

The spelling of 1625068309693 in words is "one trillion, six hundred twenty-five billion, sixty-eight million, three hundred nine thousand, six hundred ninety-three".