Base | Representation |
---|---|
bin | 10111101001100001011… |
… | …000000011101010000010 |
3 | 12202100202012022112112120 |
4 | 113221201120003222002 |
5 | 203111232110144044 |
6 | 3242324112305110 |
7 | 225261161264130 |
oct | 27514130035202 |
9 | 5670665275476 |
10 | 1625131334274 |
11 | 57723a2a8938 |
12 | 222b65242196 |
13 | ba331724436 |
14 | 5892a2a0750 |
15 | 2c417a9a519 |
hex | 17a61603a82 |
1625131334274 has 32 divisors (see below), whose sum is σ = 3777544995840. Its totient is φ = 456453352272.
The previous prime is 1625131334251. The next prime is 1625131334293. The reversal of 1625131334274 is 4724331315261.
It is a super-4 number, since 4×16251313342744 (a number of 50 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 327909414 + ... + 327914369.
It is an arithmetic number, because the mean of its divisors is an integer number (118048281120).
Almost surely, 21625131334274 is an apocalyptic number.
1625131334274 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1625131334274 is an abundant number, since it is smaller than the sum of its proper divisors (2152413661566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1625131334274 is a wasteful number, since it uses less digits than its factorization.
1625131334274 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655823854.
The product of its digits is 362880, while the sum is 42.
The spelling of 1625131334274 in words is "one trillion, six hundred twenty-five billion, one hundred thirty-one million, three hundred thirty-four thousand, two hundred seventy-four".
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