Search a number
-
+
16258051333 is a prime number
BaseRepresentation
bin11110010010000111…
…00010110100000101
31112222001101120200101
433021003202310011
5231244030120313
611245134244101
71113614104366
oct171103426405
945861346611
1016258051333
116993278667
123198956631
1316c1387524
14b03345b6d
156524ba5dd
hex3c90e2d05

16258051333 has 2 divisors, whose sum is σ = 16258051334. Its totient is φ = 16258051332.

The previous prime is 16258051297. The next prime is 16258051351. The reversal of 16258051333 is 33315085261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16257015009 + 1036324 = 127503^2 + 1018^2 .

It is an emirp because it is prime and its reverse (33315085261) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16258051333 - 233 = 7668116741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16258051292 and 16258051301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16258051373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8129025666 + 8129025667.

It is an arithmetic number, because the mean of its divisors is an integer number (8129025667).

Almost surely, 216258051333 is an apocalyptic number.

It is an amenable number.

16258051333 is a deficient number, since it is larger than the sum of its proper divisors (1).

16258051333 is an equidigital number, since it uses as much as digits as its factorization.

16258051333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 16258051333 in words is "sixteen billion, two hundred fifty-eight million, fifty-one thousand, three hundred thirty-three".